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Una celda electroquímica esta basada en estas media reacciones: Ag (ac) + le- - Ag(s) E = 0.80 V Au 3+ (ac) + 3e- Au(s) E =

An electrochemical cell is based on these reactions: Ag (ac) + le- → Ag (s) E ° = 0.80 V 3+ Au (ac) + 3e- → Au (s) E ° = 1.50 V Calculate the standard potential of the galvanic cell that can be obtained from these two half reactions and then answers: The substance that oxidizes is: The standard potential of this cell, E cell has a value of
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Answer #1

Au3 f given- Ag togte – Ag: E = 0.8V 3+ (as) tie - Aus; 6 = 1.50V Here, reduction potential of A3+ is more than Agt. 3o, A43t

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