ZuoTi.Pro
Question

Rank the following in order of strength as a reducing agent. EM Ag (aq) +e-Ag(s) +0.80 Alaq) + 3e-4Alls) 1.66 Aul(aq) + 3e- 4
science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

As the reduction potential value increases the reducing character decreases.

So one with most positive value of reduction potential will be least reducing and one with least value of reduction potential will be most reducing.

1.5> 1.19 > 0.80 > -0.14 > -0.25 > -0.28 > -0.91 > -1.66

So reducing strength will be as in decreaing order

1 Al3+

2 Cr2+

3 Co2+

4 Ni2+

5 Sn2+

6 Ag+

7 Pt2+

8 Au3+

Ranks :

Ag - 6

Al - 1

Co - 3

0 0
Add a comment
Know the answer?
Add Answer to:
Rank the following in order of strength as a reducing agent. EM Ag (aq) +e-Ag(s) +0.80...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Question 30 1 pts Rank the following in order of strength as a reducing agent. E°...

    Question 30 1 pts Rank the following in order of strength as a reducing agent. E° (V) Ag (aq) +e-4Ag(s) +0.80 Al(aq) + 3e Al(s) -1.66 Au3(aq) + 3e-Au(s) +1.50 Co2(aq) + 2e- 4 Cols) -0.28 Cr2+ (aq) + 2e-4Cr(s) -0.91 Ni?(aq) + 2e-Ni(s) -0.25 Pt2(aq) + 2e-4Pt(s) +1.19 Sn2(aq) + 2e-4Sn(s) -0.14 Ag [Choose 2 1 - strongest 3 - weakest TRUSC AI Co [Choose]

  • Use the standard reduction potentials from the following table to choose the weakest reducing agent among...

    Use the standard reduction potentials from the following table to choose the weakest reducing agent among those shown below. Ag+(aq) + - + Ag(s) E° = 0.80 V Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Ni2+(aq) + 2e + Ni(s) E° = -0.26 V Cr3+(aq) + 3e- → Cr(s) E° = -0.74 V Mn2+(aq) + 2e → Mn(s) E° = -1.19 V О Ni(s) Ag(s) Cr(s) Mn(s) Cu(s)

  • Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g)...

    Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...

  • A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...

    A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...

  • Find the best reducing agent from Cu+, Ag+ F2 and Fe3+ #1. In the reduction table...

    Find the best reducing agent from Cu+, Ag+ F2 and Fe3+ #1. In the reduction table i can see several repeated values of Fe3+ one is equal to 0.77v and the second one is equal to -0.036v so, which one do I choose? Please explain. #2.If I'm asked to find the best oxidation agent, from the values already provided (Cu+, Ag+ F2 and Fe3+) which one would it be? and how would I decide from repeated values, like in #1,...

  • Complete each of the following half-reactions with the correct number of electrons and then arrange them...

    Complete each of the following half-reactions with the correct number of electrons and then arrange them from strongest oxidizing potential to strongest reducing potential. Strongest Oxidizing Potential Drag the text blocks below into their correct order. 2e Au3+ (aq) + e + Au(s) E° = +1.50 V 5e Sn2+ (aq) + e + Sn(s) E° = -0.14 V 6e Ca2+ (aq) + 2e + Ca(s) E° = -2.87 V wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww 4e Co3+ (aq) + 2e + Co2+ (aq) E° =...

  • Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73...

    Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...

  • pls explain in great detail why Consider the following standard reduction potentials Reduction Half-Reaction A1+ (aq)...

    pls explain in great detail why Consider the following standard reduction potentials Reduction Half-Reaction A1+ (aq) + 3e A1(s) Fe2+ (aq) + 2e-Fe(s) Sn2+ (aq) + 2e - Sn(s) E (volts) -1.66 0.44 0.14 The AIAP half-reaction can be paired with the other two to produce voltaic cells because Als* is a more powerful reducing agent OOO Al is a more powerful oxidizing agent o Fe and Sn are readily oxidized Al is a more powerful reducing agent AB+ is...

  • consider the following standard reduction potentials. Reduction Half-Reaction Eo (volts) Al3+(aq) + 3e− → Al(s) −...

    consider the following standard reduction potentials. Reduction Half-Reaction Eo (volts) Al3+(aq) + 3e− → Al(s) − 1.66 Fe2+(aq) + 2e− → Fe(s)    − 0.44 Sn2+(aq) + 2e− → Sn(s) − 0.14 The Al/Al3+ half-reaction can be paired with the other two to produce voltaic cells because ________ A) Al is a more powerful oxidizing agent B) Fe and Sn are readily oxidized Al is a more powerful reducing agent C) Al3+ is a more powerful oxidizing agent D) Al3+...

  • Consider the following half-reactions and their reduction potentials (volt Au (aq) +3e- Au(s) +1....

    Consider the following half-reactions and their reduction potentials (volt Au (aq) +3e- Au(s) +1.50 petad) +2 e' → Pt(s) +1.20 Co2+(aq) + 2 e' → Cols) -0.28 Mn? (aq)+2e Mn/s) -1.18 Which one of the following statements is correct? O A Ptis) can reduce Ht in aqueous solution OB. P (ag) can be reduced by Cols) OC. A (aa) is the weakest oxidizing agent D. Mn? (aq) can oxidize Au (s) OE. Auls) is the strongest reducing agent ous Save...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT