According to a Pew Research Center study, in May 2011, 39% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 317 community college students at random and finds that 143 of them have a smart phone. Then in testing the hypotheses:
H0: p = 0.39 versus
Ha: p > 0.39,
what is the test statistic?
z = . (Please round your answer to two decimal places.)
Given Ho : p = 0.39
H1 : p > 0.39
n = 317 and x = 143
Let sample proportion p^ = 0.45
Test statistic Z
Z = p^ - p /(p *(1-p)/n)
Z = 0.45 - 0.39/sqrt(0.39*0.61/317)
Z = 2.19
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According to a Pew Research Center study, in May 2011, 31% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 352 community college students at random and finds that 129 of them have a smart phone. In testing the hypotheses: H0: p = 0.31 versus Ha: p > 0.31, she calculates...
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