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Consider the equilibrium of a foot for a crouching 220-lb person. The force through the Achilles tendon (T), the force of the2) Find the magnitude of the Achilles tendon tension (T) by knowing the total torque about the bottom of the tibia is zero. (

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Answer #1

1) The normal force supports a half of the weight of the person, so: 220 N-W V=2= = 110 lb Torque about the tibia: t = 0 N(1.

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