When a person stands on tiptoe (a strenuous position), the position of the foot is as...
e Physics 115 Chapter Of8 erCP11 8.3.P.024. hen a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure a. The total gravitational force on the body, F is supported by the force n' exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure b, where T is the force exerted by the Achilles tendon on the foot and R is the force...
thanks! 14 -13 poits SerPOP4 10 PO7O. My Notes Ask Your When a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure P10.70a. The total gravitational force on the body, rg, is supported by the force n exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure P10.70b, where T is the force exerted by the achilles tendon on the foot and...
read the question carefully please. A 10 000-N shark is supported by a cable attached to a 4.00-m rod that can pivot at its base. Calculate the ten sion in the tie-rope between the wall and the rod if it is holding the system in the position shown in Figure P12.49. Find the horizontal and vertical forces exerted on the base of the rod. (Neglect the weight of the rod.) where T is the force exerted by the Achilles tendon...
20.0 I- A 10 000-N shark is supported by a cable attached to a 4.00-m rod that can pivot at its base. Calculate the ten- sion in the tie-rope between the wall and the rod if it is holding the system in the position shown in Figure P12.49. Find the horizontal and vertical forces exerted on the base of the rod. (Neglect the weight of the rod.) where T is the force exerted by the Achilles tendon on the foot...
Consider the equilibrium of a foot for a crouching 220-lb person. The force through the Achilles tendon (T), the force of the tibia (F), and the normal force (N) from the floor are shown in the figure below. The weight of the foot has been neglected for simplicity. Take the angle that the Achilles tendon makes with the horizontal to be a 36 degrees 2.35" 1.9 What is the normal force (N) on the foot? (Express your answer to two...
A 75 kg person is crouching with his weight evenly distributed on both tiptoes. The forces on the skelet part of foot are shown in Fig. 12.9 below. In this position, the Achilles tendon experiences a force F., making an angle a = 59.2° with the horizontal. The tendon acts on the ankle a horizontal distance d= 9.66 cm from the point where foot touches the floor. The tibia acts on the foot with magnitude | F and makes an...
In the figure below the foot of a walking person is momentarily in contact with the ground and approximately in static equilibrium. The foot bears the person's full weight of 537 N(N-W-537 N). (Let D-11.4 cm and d - 4.70 cm.) (a) Compute the tension in the Achilles' tendon (b) Compute the horizontal and vertical components of the force P at the ankle.
A person is doing leg flexion/extension exercises from a sitting position in order to strengthen the person's quadracept muscles. The forces acting in the lower leg are illustrated in the figures below. W0 is the weight of the boot, W1 = 160 N is the weight of the person's lower leg, FM is the magnitude of the force exerted by the quadricepts muscle on the tibia (shinbone) through the patellar tendon, and FJ is the force due to the tibiofemoral...
The Achilles tendon is located on the back of the ankle as far as possible from the ankle joint (6 cm) to give the calf muscles (gastrocnemius and soleus) the maximum advantage lifting the body. Assume a 98 kg basketball player (weight of 961 N) with a foot length of 30 cm is jumping from the right foot with only the ball of the foot in contact with the floor. a) Assuming static equilibrium, how much muscle force (G) in...
To understand the two most common procedures for finding torques when the forces and displacements are all in one plane: the moment arm method and the tangential force method. The purpose of this problem is to give you further practice finding torques in two-dimensional situations. In this case it is overkill to use the full cross product definition of the torque because the only nonzero component of the torque is the component perpendicular to the plane containing the problem. There...