Question

Forthecomplexion [Pd(acac)Cl(H2O)2NH3] + Palladiumisinthenickelfamily. (Write answers on blanks provided).

(a) Number of valence d electrons and charge of central metal ion equals,

Valence d electron count: ___________ Charge of central atom: ____________ (b) Name the complex ion: (no abbreviations)

Name:______________________________________________________________________ (c) Show the crystal field orbital diagram of the central metal ion. Assume that all the

ligands in this complex ion follow the same trend as you memorized for oxalate “ox”.

(d) Draw all the unique structural isomers of this complex ion. Neatness counts and the drawings should bear some close resemblance to the angles of the geometry. Redundancy will be marked off.

e) Ion is paramagnetic diamagnetic?

  

Can an expert please help me solve the question above? Please show work.

Answer 1

+ chlore=cl - = -1 Udo acac = 0 ) a = -1 pak a HN OH, acetylacetonate ammine=NHą = Neurtral aqua = H₂O = Neustral distorted octahedral *(x) o.s of Pd a => @ d7, +3,0-s x + (-1-1) = +1 & Asumine. 6 Acetyl acetonato Ammine diaqua chloro a=+3] Palladium (II). x - 2 x = +1 +1+2 = © D7 +0.6 liliit .. -..- Berry center -0.9 spin complexe 4d & 5d series (elements) Metats form low wether the ligand is strong or weak. H20 e H₂O a pl. 120 LOSINHz bo xo-pd- H₂O one H₂O ch NH3 o - H2O Mac H2O on pd - NH3 HN pd- H₂o I cd ; d l H2O PdNH3, HNPdo TH₂O 48 14 H20 Total ion is 8 isomer paramagnetic set has one unpaired electron. @