read the question carefully please.
Here for problem 1 solution is as given below,
read the question carefully please. A 10 000-N shark is supported by a cable attached to...
20.0 I- A 10 000-N shark is supported by a cable attached to a 4.00-m rod that can pivot at its base. Calculate the ten- sion in the tie-rope between the wall and the rod if it is holding the system in the position shown in Figure P12.49. Find the horizontal and vertical forces exerted on the base of the rod. (Neglect the weight of the rod.) where T is the force exerted by the Achilles tendon on the foot...
19. A 10 000-N shark is supported by a cable attached to a 4.00-m rod that can pivot at the base. Calculate the tension in the tie-rope between the rod and the wall if it is holding the system in the position shown in Figure P12.49. Find the horizontal and vertical forces exerted on the base of the rod. (Neglect the weight of the rod.) 20.01 10 000N 0.0 Figure P12.49
A 11000 N shark is supported by a cable attached to a 4.60 m rod that can pivot at the base. (a) Calculate the tension in the tie-rope between the rod and the wall if it is holding the system in the position shown in Figure P12.49. (Neglect the weight of the rod.) (b) Find the horizontal force exerted on the base of the rod. Magnitude kN Direction to the right to the left (c) Find the vertical force exerted...
A 10200-N shark is supported by a rope attached to a 3.40-m rod that can pivot at the base. A rod is attached to a pivot at the base of a wall on the left. The rod extends up and right at a 60.0° angle from the horizontal. A cable connected to the top end of the rod extends up and left at a 20.0° angle from the horizontal before connecting to the wall. A shark hangs from a rope at the top...
A 9 600-N shark is supported by a rope attached to a 5.00-m rod that can pivot at the base. (a) Calculate the tension in the cable between the rod and the wall, assuming the cable is holding the system in the position shown in the figure. (Give you answer to three significant digits.) (b) Find the horizontal force exerted on the base of the rod. magnitude=? direction=? (c) Find the vertical force exerted on the base of the rod....
e Physics 115 Chapter Of8 erCP11 8.3.P.024. hen a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure a. The total gravitational force on the body, F is supported by the force n' exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure b, where T is the force exerted by the Achilles tendon on the foot and R is the force...
When a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure a. The total gravitational force on the body, Fe, is supported by the force n exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure b, where T is the force exerted by the Achilles tendon on the foot and R is the force exerted by the tibia on the foot....
thanks! 14 -13 poits SerPOP4 10 PO7O. My Notes Ask Your When a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure P10.70a. The total gravitational force on the body, rg, is supported by the force n exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure P10.70b, where T is the force exerted by the achilles tendon on the foot and...
A 1,500-N uniform boom at q = 63.0° to the horizontal is supported by a cable at an angle 0 = 27.0° to the horizontal as shown in the figure below. The boom is pivoted at the bottom, and an object of weight w = 2,450 N hangs from its top. OL Pivot (a) Find the tension in the support cable. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully....
To understand the two most common procedures for finding torques when the forces and displacements are all in one plane: the moment arm method and the tangential force method. The purpose of this problem is to give you further practice finding torques in two-dimensional situations. In this case it is overkill to use the full cross product definition of the torque because the only nonzero component of the torque is the component perpendicular to the plane containing the problem. There...