here,
the angle with the surface of water ,theta = 36 degree
the angle of incidence , i = 90 - theta
i = 54 degree
let the angle of refraction be r
the useful equation here is:
sin(i) / sin(r) = index of refraction of water / index of refraction of air
sin(54)/sin(r) = 1.33 /1
r = 37.5 degree
the angle of refraction is 37.5 degree
a ray of light strikes the surface of water (n=1.33) at an angle of 36 degrees....
A ray of light strikes the surface of water (n = 1.33) at an angle of 60.0° from the water surface. What is the angle of refraction? ***Don’t forget to measure angle from the normal*** Question 9 options: a) 30.0° b) zero c) 22.1° d) 60.0°
Light that is traveling through water (index of refraction is n=1.33) strikes a glass surface (index of refraction n=1.50) at an incident angle of θi=48.1°. What is the the angle of refraction, θr, of the light in the glass? Light that is traveling through glass (index of refraction is n=1.50) strikes an air surface (index of refraction n=1.00) at an incident angle of θi=27.9°. What is the the angle of refraction, θr, of the light in the air? Water Glass
A light ray in air is incident on the surface of water (index = 1.33) at an angle of 60 degrees to the normal to the surface. What is the angle of the refracted ray in the water relative to the normal? refraction cannot occur 48 degrees 49 degrees 41 degrees 68 degrees
An aquarium filled with water (n = 1.33) has flat glass sides whose index of refraction is 1.55. A beam of light from outside the aquarium strikes the glass at a 43.5∘ angle to the perpendicular (Figure 1).A) What is the angle of this light ray when it enters the glass?B) What is the angle of this light ray when it enters the water?
1.33 1. Light travels from glass to water. It strikes the boundary at an angle of 45 degrees. At what angle is the refracted ray in the water? Tour dot snell's Law = n, sing, = n₂sina O a= na sinde Az = 1 o sin45 - 12 The mount Port nge. The e an
2. A ray of light propagates in air (n= 1.33) and strikes a sheet of crown glass (n=1.523). If angle of refraction in glass is 35.2°, determine the angle of incidence. A) 30.3°, B) 32.8°, C) 35.2°, D) 41.20, E) 45.0°
A ray of light propagates in air (n= 1.33) and strikes a sheet of crown glass (n=1.523). If angle of refraction in glass is 35.20, determine the angle of incidence. Show Work A) 30.30 B) 32.80 C) 35.20 D) 41.20 E) 45.0
2. Suppose a ray of light travels from air (n 1.00) into water (n 1.33). Use Snell's law to calculate the refraction angle in the water if (a) the ray is perpendicular to the surface of the water, and (b) if the angle of incidence is 30°. Sketch both cases.
4. a. A ray of light in water (n = 1.33) encounters an interface with a piece of glass (n = 1.65). If the "grazing angle” (angle to the interface) is 30° in the water, calculate the angle of refraction of the ray in the glass. Sketch the ray in both media, correctly showing its "bend.” (Optional: Sketch the reflected ray, too.) 30° nwater = 1.33 n glass = 1.65 angle of refraction in glass: A. 37.4 B. 39.5° C....
3. A ray of light passes from water (nw= 1.33) into carbon disulphide (n = 1.63) with an angle of incidence of 30°. What is the angle of refraction in the carbon disulphide? 4. A ray of light in air has an angle of incidence of 30° on a block of unknown material and an angle of refraction of 20°. What is the index of refraction of the material?