An ideal refrigerator does 105.0 J of work to remove 555.0 J of heat from its cold compartment during each cycle. What is the refrigerator's coefficient of performance?
Tries 0/12 |
How much heat per cycle is exhausted to the kitchen?
coefficient of performance is
k = 555/105
k = 5.285
exhaust heat = 105 +555
= 660 J
An ideal refrigerator does 105.0 J of work to remove 555.0 J of heat from its...
Suppose that a certain refrigerator is observed to remove 23 J of heat from its interior, while drawing 12 J of energy from the electric grid and exhausting 35 J of heat to the kitchen in which it sits. If the food inside the refrigerator is maintained at 2.85C and the room temperature of the kitchen stays at 62.85C, then at what fraction of this refrigerator's theoretical maximum possible coefficient of performance is its current operating coefficient of performance?
A refrigerator requires 25 J of work and exhausts 45 J of heat per cycle. What is the refrigerator's coefficient of performance?
A refrigerator requires 20 J of work and exhausts 70 J of heat per cycle. What is the refrigerator's coefficient of performance?
A refrigerator has a coefficient of performance of 1.15, and it extracts 7.95 J of heat from the cold reservoir during each cycle. (a) How much work is done on the gas in each cycle? (b) How much heat is exhausted into the hot reservoir in each cycle? I've seen a similar question, but I still don't understand how to solve. Can I get help please, step by step would be kind.
A refrigerator with a coefficient of performance of 1.80 absorbs 3.15×104 J of heat from the low-temperature reservoir during each cycle. How much mechanical work is required to operate the refrigerator for a cycle? How much heat does the refrigerator discard to the high-temperature reservoir during each cycle?
A)How much mechanical work is required to operate the refrigerator for a cycle? B)How much heat does the refrigerator discard to the high-temperature reservoir during each cycle? A refrigerator with a coefficient of performance of 1.77 absorbs 3.64x104 J of heat from the low- temperature reservoir during each cycle.
You place your lunch leftovers in the refrigerator. Suppose the refrigerator needs to remove 9.8700E+3 J of thermal energy from your lunch to cool it to the temperature of the inside of the refrigerator. In the meantime, this means the refrigerator produces 1.3702E+4 J of thermal energy that it expels into the kitchen as a result. What is the total work done by the compressor motor in the refrigerator?(Ignore any thermal loses due to friction in the motor.) 3.832×103 J...
An ideal refrigerator extracts 410 joules of heat from a reservoir at 290 K and rejects heat to a reservoir at 488 K. What is the ideal coefficient of performance and how much work is done in each cycle?
An ideal refrigerator extracts 420 joules of heat from a reservoir at 280 K and rejects heat to a reservoir at 498 K. What is the ideal coefficient of performance and how much work is done in each cycle? COP = Number Work = Number Joules
37. A refrigerator uses 40 J of work to extract heat from a heat reservoir at 0.00°C. If the coefficient of performance of the refrigerator is 2.1, then how much heat is extracted from the heat reservoir at 0.00°C? 90 J 84 J 48 J 65 J