Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the...

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Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the...

Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the left ventricle of the heart. Determine (a) the acceleration of the blood and (b) the duration of the acceleration.

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Answer 1

Answer #1

a]Using third equation of motion,

v^2 = 2gh

0.295^2 = 2*a*1.79e-2

a = 2.431 m/s^2 answer

b] t = v/a = 0.295/2.431 = 0.1213 s answer

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Answer 2

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Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the...

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Add Answer to: Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the...

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Blood is accelerated from rest to 29.5 cm/s in a distance of 1.79 cm by the...