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I worked this but would love feedback or to see if I did it correctly. Thank you. The second picture is what they asked to go by.
A-3. Derive the result in Section A. Step 8. Hint: For the field E to be zero, the vectors E, and E2 must be equal in magnitude and opposite in direction, Since both charges are negative, the fields E, and Ez point toward the corresponding charges. The only points where the fields are in opposite directions are points between the two charges on the x-axis. This gives: ku Use this equation to find the x-coordinate of the position where the net field is zero, uadrotic Equetmon needed Q,-2 x 10 Rosman : (r. .。) a1 Y. 2-x 0.5x+2x2-2o 20o5) -(.828
Select the third charge configuration (Q12 HC and Q2--3 HC), check Show Axes. Click and drag the locator to a position along the -axis between the two charges. Find the position on the x-axis where the electric field equals zero. Record this position in the space below. (The best you will be able to do is to find where both components of are small compared to the components of El andE2. It suffices for the components to be less than 0.5 x 103 N/C.) This position will be calculated in a later question Position: (ll,o)
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1Qg] llere.Hao pointa changes are an ơn, line so 10 s Sueficient -o describing RX 10 2 x2 anslt 2 0.99( 8.99

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