Question

Electric Fields Equipment and Setup: Mathematica file- ElectricFields.nb Section A: Electric Fields Due to Two Charges Computer Setup for Section A 1. The first interactive panel shows electric fields due to two point charges, Qat (-1 m,0) and Q, at (1 m,0). The controls for this panel are at the top on the left 2. The top line has two checkboxes: one to Show Axes and the other to Show Field Lines. The top line also has a slider labeled "Scale Factor"; this rescales the electric field vector arrows relative to the drawing. Click the checkboxes and move the slider to see what happens. To undo any changes, click the Reset button on the upper right of the panel. 3. The next line has buttons with three different values of the charges. Click these to see what happens. 4. The third line selects the point where the fields are evaluated. The five buttons give preset values for the x- and y-coordinates of this point. point to any position. Try this. You can also drag the "locator" (crosshairs) to move the evaluation 5. At the right of the control panel, the x- and y-components of the fields are shown. The vectors E, and E, are the electric fields due to Q and Q, respectively; these are displayed with the green arrows in the picture. E is the total field, the vector sum of E, and E Data Recording for Section A 1. Select the charge configuration Q, =-2 pC and Drag the locator to move the evaluation position along the y-axis. In the space below, describe the direction of the field along the y-axis. +2 AC (called a dipole) and check Show Axes. The direction ot on the yrexis the Held is alweys the eft sade 2. Select thesecond ch ge configuration (Q--2pC and Q-+3pC), check Show Axes and select the position (0,1 m). In the space below, record E. E, and E. These electric field vectors will be calculated in a later question. E-615m1씨n)x103 Me 3. Select the third charge configuration (Q-2 pC and Q, 3 μ。) with Show Axes checked drag the locator to a position along the x-axis between the two charges. Find the position where the electric field becomes zero. Record this position in the space below. (It suffices for the components to be less than 0.5x10 N/C, which is sufficiently small compared to E, and E.) This position will be calculated in a later question. 0,0) m

Answer 1

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