The normal boiling point of Br2(l) is 58.8 ∘C, and its molar enthalpy of vaporization is...

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The normal boiling point of Br2(l) is 58.8 ∘C, and its molar enthalpy of vaporization is...

The normal boiling point of Br2(l) is 58.8 ∘C, and its molar enthalpy of vaporization is ΔHvap = 29.6 kJ/mol.

Calculate the value of ΔS when 4.00 mol of Br2(l) is vaporized at 58.8 ∘C.

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geven DH vap = 29.6kI/mol T - 58.8°C - 27 3t 58.8 - 33108A moles (n) = 4.00 mal. As = (sthaplen 1 29.6x4 33108 AS = 0.357 kJ please please please please please please like like like like like

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