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In the figure that shows the coefficient of static friction between the mass mA and the table is 0.40 while the coefficient of kinetic friction is 0.30. Determine the minimum value of mA that would maintain the system without moving

mA ntp 2.0 kg
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Answer #1

Tension in the rope T=20\textup{ N}

For the block A

T=F

where F is the friction force

F\leq\mu_s m_Ag

\Rightarrow \frac{F}{\mu_s g}=5\leq m_A

Thus, minimum mass of A required is 5 kg

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