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An old tablet of vitamin C weighed 1.022 g. It was dissolved in 500. mL water, and a 25.0 mL aliquot of this solution require

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Answer #1

weight of the tablet = 1.022 g

it was dissolved in 500 ml and from that 25 ml was taken for analysis

22.6 ml of 0.00500 M I2 solution required

moles of I2 required = 0.0226*0.00500 = 1.13*10^-4 M

so moles of vitamin C present in the 25 ml aliquot = 1.13*10^-4 M

vitamin C present in the stock = 2.26*10^-3 M

Amount of vitamin C in the tablet = 176.12*2.26*10^-3*1000 = 398 mg

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