Question

Chapter 02, Problem 10 In reaching her destination, a backpacker walks with an average velocity of 1.03 m/s, due west. This average velocity results, because she hikes for 5.56 km with an average velocity of 3.03 m/s due west, turns around, and hikes with an average velocity of 0.470 m/s due east. How far east did she walk (in kilometers)? dw West East Units Number the tolerance is +/-590

Answer 1

net average velocity due west-vavg-1 .03 initital average velocity-vwー3.03-due west and dis tan ce -d -5.56 km time t- Sec d 5.56km 1834.983 sec .. Im Vw 3.0.3 and average velocity due east -VE--0.470 m/s dis tan ce travelled d E VE time -tp Im net average velocity = V --W avg Sec => 5560-0.4706, = 1.03(tw +t.) > t 2446.647 1 sec we plug the values in hand while using the relation give us dr -1.15 km