Homework Answers
Given:
Concentration on the outside of a membrane: 5.00 mM
Concentration on the inside of a membrane: 4.00 
M = 0.004 mM
To calculate: The potential energy change
Therefore,
where R=1.987 cal/(degreeK.mol), T=298 K
Substituting the values,
4222.39 cal/mol
= 4.2 kcal/mol
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Caculate the PH THANK YOU!
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