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1. (22.4) Richard Feynman (1918-1988) once said if two people stood at arms length from each other and each person had 1% more electrons than protons, the force of repulsion between them would be enough to lift a weight equal to that of the entire Earth. Do an order-of- magnitude calculation to show this. Be sure to communicate assumptions and estimates. 2. (23.20) A particle with charge Q is located at the center of a cube with edges of length L Also, six other identical charged particles of charge q are positioned symmetrically around Q as shown in the figure below. Assume q is a negative number. Determine the electric flux through one face of the cube.

I have been struggling with these two practice problems in the book, thanks for the help in advance!

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Answer #1

Richard Feynman assEdition is true.

Solution

Suppose their masses are of the order 102 kg If protons constitute half of total mass - other half being neutrons, there will be the same number of electrons as protons in neutral matter. So, 1% electrons will be same as 1% protons. Protons-102 kg/ [1 .673x10-27 kg-6x1028 protons If there is a net charge of 1% of total electrons than protons, q-01-a2-(1 /100)x 6x1 028 proton charge proton charge eletron charge e 1.602x10 28 So, q = (1/10Ox 6x10 x 1.602x10-19 C-~ 10% So, using F Kq/R, where R - distance 1m, K 9x109~ 1010, q ~10° C, F~ 1026N For lifting Earth, gravitational force-Fg = Mearth x g Mearthä 6 x 1024 kg g~10 m/s2 So, Fg ~1026 N So, clearly the assertion is true!

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