Question

I need help with these two problems. I

got the formula for the second one but I don't understand how to solve for q and 2q in order to find x.

Please Help

1. +-/3 points SerPSE10 22.3.P.004 My Notes Ask Your Teacher Nobel laureate Richard Feynman (1918-1988) once said that if two persons stood at arms length from each other and each person had 1% more electrons than protons, the force of repulsion between them would be enough to lift a weight equal to that of the entire Earth. Carry out an order-of-magnitude calculation to substantiate this assertion F~ 10 Need Help?ReadIt Submit Answer Save Progress 2.+-/2 points SerPSE10 22.3.P.007 My Notes Ask Your Teacher Two small beads having positive charges q1 = 29 and q,-q are fixed at the opposite ends of a horizontal insulating rod of length d = 1.50 m. The bead with charge q1 is at the origin. As shown in the figure below, a third small, charged bead is free to slide on the rod 1 42 (a) At what position x is the third bead in equilibrium? (b) Can the equilibrium be stable? O Yes, if the third bead has a positive charge O Yes, if the third bead has a negative charge No Need Help?ReadWatch

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Answer #1

Assumption:-

Let the mass of each person =  100kg

Distance between both the person  r=1m

If protons constitute half of total mass - other half being neutrons, there will be the same number of electrons as protons in neutral matter.

So, 1% electrons will be same as 1% protons.

therefore

102 1.673 × 10-27 Protons =

Protons 6 × 102

which gives us the number of protons

Now,

If there is a net charge of 1% of total electrons than protons,

= qi = q2 =- 100 × 6 × 1028( proton charge)

proton charge = eletron charge  

which is

e1.602 x 10-19o

So,

× 6 × 1028( 1.602 × 10-19) ะ 108c 100

we know that

F = rac{Kq^2}{r^2}

by plugging all the values we get

F= (9 × 109)(108)2

which gives us

F 1026N

Now,

The force required for lifting Earth,

gravitational force  F_g = M_{Earth} imes g

MEarth -б x 1024 kg,0% 10m/s2

thus

F1026N

So we can clearly see that  F approx F_g

Hence the assertion is ture

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