Question

5. O-4 points SerPSE9 29 P059.MILFB. My Notes Ask Your Teacher A particle with positive charge q 8.01 x 10 -19 C moves with a velocity v (5i 2 k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B- (5i 3j T and E (2i j 4k) V/m. (b) What angle does the force vector make with the positive x axis? Need Help? ReadR 6. 111 points I Previous Answers SerPSE9 29 P061 My Notes Ask Your Teacher The unner nortion of the circuit in the fiaure helow is fixed. The horizontal

Please solve both qustions the second one part b

Answer 1

F bar rightarrow = q(E bar rightarrow + v bar rightarrow times 8 bar rightarrow) = (801 times 10^-19)[(2x^- y^- 4z^) + (5 x^+ 2y^- z^) times (5 x^+ 3y^+ z^0 = [8.01 times 10^-19)[2x^- y^+ 4z^+ x^(2 + 3) + y^(-5 - 5) + z^(15 - 10) = [(56.07 x^- 88.11 y^+ 72.09 z^) times 10^-19]N (b) theta = cos^-1(56.07/squareroot (56.07^2 + 88.11^2 + 72.09)^2) = 63.78 degree (b) v = squareroot 2k/m = squareroot 2(5.08 times 10^6)(1.6 times 10^-10)/1.67 times 10^-27) = 3.12 times 10^7 m/s because magnetic filed can't change velocity magnitude it remains the same Now, therefore theta = 8.87 degree v_y = v sin theta = 4.82 times 10^6 m/s