AlCl3 ------> Al3+ + 3Cl-
from equation :
1 mol AlCl3 = 1 mol Al3+ = 3mol Cl-
No of mol of Cl- ions = 3*7.5= 22.5 mol
No of Cl- ions = 22.5*6.023*10^23 = 1.35*10^25 Ions
So option A is correct
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