Question

help me.

Be sure to answer all parts. How many moles and numbers of ions of each type are present in the following aqueous solution? Give your answers for the numbers of ions in scientific notation. 602 mL of 0.122 M aluminum chloride mol aluminum x 10 ions of aluminum mol chloride x 10 ions of chloride

Answer 1

Answer

0.073444 mol aluminium

4.42 ×10²² ions of aluminium

0.22033 mol chloride

1.33 ×10²³ ions of chloride

Explanation

Molarity = number of moles of solute per liter of solution

Number of moles of aluminium chloride = (0.122mol/1000ml)×602ml = 0.073444mol

Formula of aluminium chloride : AlCl₃

one aluminium chloride contains one aluminium ion and three chloride ions

Therefore

Number of moles of aluminium ion = 0.073444mol

Number of moles of chloride ion = 3 × 0.073444mol = 0.22033mol

1mole = 6.022×10²³ions

Number of aluminium ions = (6.022×10²³ions/ 1mol)× 0.073444mol = 4.42× 10²² ions of aluminium

Number of chloride ions = (6.022×10²³ions/1mol) × 0.22033mol = 1.33 × 10²³ ions of chloride