Molar mass of Ca(NO3)2,
MM = 1*MM(Ca) + 2*MM(N) + 6*MM(O)
= 1*40.08 + 2*14.01 + 6*16.0
= 164.1 g/mol
mass(Ca(NO3)2)= 9.75*10^-5 g
number of mol of Ca(NO3)2,
n = mass of Ca(NO3)2/molar mass of Ca(NO3)2
=(9.75*10^-5 g)/(164.1 g/mol)
= 5.941*10^-7 mol
1 molecule of Ca(NO3)2 has 3 ions
So,
number of mol ions = 3*5.941*10^-7 mol
= 1.78*10^-6 mol
Answer: 1.78*10^-6 mol
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