Question

Be sure to answer all parts. How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientific notation. 1.94 10-g of NiBr2 · 34,0 - 1 x 10 mol

Answer 1

Total moles of ions released = 2.14 x 10^-3 mol

Explanation

mass NiBr₂.3H₂O = 0.194 g

moles NiBr₂.3H₂O = (moles NiBr₂.3H₂O) / (molar mass NiBr₂.3H₂O)

moles NiBr₂.3H₂O = (0.194 g) / (272.5472 g/mol)

moles NiBr₂.3H₂O = 7.12 x 10^-4 mol

moles Ni²⁺ = moles NiBr₂.3H₂O

moles Ni²⁺ = 7.12 x 10^-4 mol

moles Br^- = 2 * (moles NiBr₂.3H₂O)

moles Br^- = 2 * (7.12 x 10^-4 mol)

moles Br^- = 1.42 x 10^-3 mol

Total moles of ions released = (moles Ni²⁺) + (moles Br^-)

Total moles of ions released = (7.12 x 10^-4 mol) + (1.42 x 10^-3 mol)

Total moles of ions released = 2.14 x 10^-3 mol