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1.(3pts) Use the following data to determine the AH of > 8 CO (g) +5 H2O() 2 C Hiog) +13 O2(g) AH (KJ/mol) Substance AH (kJ/m
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Answer #1


2C4H10 + 13 O2 ---> 8 CO2 + 5H2O(l)
dHrxn = dHf[products] - dHf(reactants]
= 8*dHf(CO2) + 5*dHf(H2O) - { 2*dHf(C4H10) + 13*dHf(O2)}
= 8*[-393.51 KJ] +5*[-285.83 KJ] - 2*[-126.15 kj]-0 KJ
= -3148.08 kj -1429.15 KJ +252.3 KJ = -4324.93 KJ

dHrxn =-4324.93 KJ
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:) thanks!!

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