initial mass = 10.0 g
remaining mass = 1.25 g
time = 100 min
for first order :
rate constant = 1/t ln (Ao / At)
= 1/ 100 ln (10 / 1.25)
k = 0.0208 min-1
half - life = 0.693 / k
= 0.693 / 0.0208
half - life = 33.33 min
Rate law = k [X]
rate = 1/ t ln [Ao / At]
If 10.0 g of a substance A decomposes for 100 min, the mass of A remaining...
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