Given:
pKa = 10.00
[C6H5OH] = 1.6 M
[C6H5O-] = 1.2 M
use:
pH = pKa + log {[conjugate base]/[acid]}
pH = pKa + log {[C6H5O-]/[C6H5OH]}
= 10+ log {1.2/1.6}
= 9.875
Answer: 9.87
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