Given:
pKa = 8.64
[HBrO] = 0.59 M
[BrO-] = 0.48 M
use:
pH = pKa + log {[conjugate base]/[acid]}
pH = pKa + log {[BrO-]/[HBrO]}
= 8.64+ log {0.48/0.59}
= 8.55
Answer: 8.55
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