Answer:
1) z = 0.52, =0.05
Right tailed test
P-Value = 1 - P(z < 0.52)
find P(z < 0.52) using normal z table
we get,
P(z < 0.52) = 0.6985
P-Value = 1 - 0.6985
P-Value = 0.3015
Since (P-Value = 0.3015) < (=0.05)
Reject Ho.
0.3015; Reject Ho.
2) Two tailed test, =0.10
find critical z value using normal z table
we get,
-Z0 = -1.645, Z0 = 1.645, Z< -1.645, Z> 1.645
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