How much heat is gained by nickel when 29.2 g of nickel is warmed from 18.3°C...

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Question

Answer 1

Answer #1

The heat gained by nickel during heating , q = m*s*DT where m is mass of water, s is specific heat of nickel and DT is change in temperature.

The heat gained by nickel during heating , q = m*s*DT = 29.2*0.443*(69.6-18.3) = 663.59 joules = 6.64*10^2 joules.

Q No: 11

heat lost by metal = heat gained by water

m1*s1*DT1 = m2*s2*DT2

m1 = mass of metal = 170 g

s1 = specific heat of metal = ?

DT = (78-17.9) c

m2 = mass of water = 170 g

s2 = specific heat of water = 4.184 j/g.c

DT2 = (17.9-15) c

170*S1*(78-17.9) = 170*4.184*(17.9-15)

S1 = specific heat of metal = 0.201 j/g.c

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Answer 2

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