Question

A 200.0 G CHINA SERVING BOWL IS WARMED 65.0 c WHEN IT ABSORBS 2.6 kcal of heat from a serving of hot food. what is the specific heat of the china dish?

please show work

Answer 1

      The mass of the china dish, m = 200 g

      The change in temperature, ΔT = 65.0^oC

      The heat energy, Q = 2.6 kcal

                                     = ( 2.6 kcal)(1000 cal/1 kcal)

                                     = 2600 cal

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      The relation between the heat flow and specific heat is

                                      Q = mcΔT

      So, the specific heat of the china dish is

                           c = Q/mΔT

                              = (2600 cal)/(200 g)(65.0^oC)

                              = 0.2 cal/g.^oC

Note:

        1 cal = 4.186 J

          1 g = 10^-3 kg

         c = (0.2)(4.186/10^-3) J/kg.^oC

            = 837.2 J/kg.^oC