Question

For the hypotheses below, test a = 0.025 with n= 100 and p = 0.67. State a. the decision rule in terms of the critical value

I don't know how to do c. The conclusion.

Thanks in advanced for the help.

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Answer #1

This is the left tailed test .

Z 0.025 = -1.645

Critical value = -1.645

\hat p = x / n = 0.67

Test statistic = z

= \hat p - P0 / [\sqrtP0 * (1 - P0 ) / n]

= 0.67 - 0.76 / [\sqrt(0.76 * 0.24) / 100]

= -2.107

(c)

|z| > -1.645

Reject the null hypothesis

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