Question

1) Suppose you are trying to determine the identity of the metal ions in your unknown mixture for this lab and you find that after step 1 you have a precipitate. You separate the precipitate from the solution and perform step 2 (on the precipitate) and step 3 (on the solution). Your results of step 2 do not yield a precipitate. Your results from step 3 yield a precipitate. Which spot tests should you run to completely determine the identities of your unknowns? Explain your reasoning.

1) Suppose you are trying to determine the identity of the metal ions in your unik for this lab and you find that after step 1 you have a precipitate. You separate the p entity of the metal ions in your unknown mixture from the solution and perform step 2 (on the precipitate) and step 3 (on the solum have a precipitate. You separate the precipitate results of step 2 do not yield a precipitate Your results from step 3 yield a precipitate spor tests should you run to completely determine the identities of your unknowns CEP reasoning

Answer 1

are Normally, metals prepitation idenhlied by transition reaction (widely used in case of (widely used metal) metals combines with various ligands. which are mostly basie in nature and forms precip chargeless complexes which does not allows them to dissolves in sol? - & Now if this chargeless complex can be mache in form tcharged complex it can redissolve in sol? Now once it got dissolved in sol? as. mt we can easily determine the name of metal as they # mostly form coloured solo on reacting with various reagents. procedure for metal detection : a dissolve UUUUUUU it in a solvent Unknown mixture add ligand (x) IMG chargeless species to remains as pet . (1) Take precipitated sold (2) Take sol? or mostly (solrent) JJJJJJ. add another li's and which makes it charged No effect complex formation. + 2 A charged complex . Dissolves in sol?

For determination of ((u) stepil Curss 2 + on dissolve in water [Cu CH₂O) ] ingh add base like (NaOH, koH) Cu CH20) 4C014)2] it is chargeless here remains as is) le precipitate Step 2 e Ast conversion from chargeless to a charged compound [Ca (H₂O) Conan o add NH₃ (excess) [[u CH2) (NH3)4] et 199) : soluble in sol? (Dark blue colour) Now this can be determination. used for further

ACC to your question : step :I - ppt + sol? 101. step. I step II ste dissolves ppt No Metal go further with this one as it contains your metal