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carbonate ions from a soluble metal carbonate (M2CO3) will be quantitatively isolated as CaCO3(s) by precipitation...

carbonate ions from a soluble metal carbonate (M2CO3) will be quantitatively isolated as CaCO3(s) by precipitation using CaCl2 (aq) followed by filtration according to the following reaction:

CaCl2(aq) + M2CO3(aq) CaCO3(s) + 2 MCl(aq)

Determine the exact mass of unknown you started with and the mass of precipitate produced from it and identity for the metal in your unknown,it is a group IA metal carbonate you were given.

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