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04 (a) Calcium ions can be determined by precipitation of the oxalate according to the equation:...
Scoring Scheme: 3-3-2-1 Part V. The chemical system containing the simultaneous equilibria involves the precipitation of...
Scoring Scheme: 3-3-2-1 Part V. The chemical system containing the simultaneous equilibria involves the precipitation of calcium oxalate in the presence of a weak diprotic acid, oxalic acid: Ca2+(aq) + C2042-(aq) ; CaC204(s) H2C204(aq) H20()FH30* (aq) HC204 (aq) HC204(aq)+ H20)H3(aq)+ C2042(aq) You added 10 drops of 6 M HCI to the solution of calcium chloride and oxalic acid. Which of the following statements explains your observations? a. The addition of H30t shifts the oxalic acid equilibria to the left, decreasing...
1. When iron(II) ammonium sulfate is dissolved in water, it dissociates into its component ions. ()...
1. When iron(II) ammonium sulfate is dissolved in water, it dissociates into its component ions. () → () + ( ) + ( ) 2. When oxalic acid is added, the iron (II) ions precipitate as iron(II) oxalate dihydrate. Fe2+ (aq) + (aq) + __H20 (1) ► ( ) + _ H(aq) 3. Next, potassium oxalate is added to the washed precipitate. Potassium oxalate dissociates into its ions in solution. At high oxalate concentrations, iron (II) oxalate combines with another...
The excess hydroxide ions must be neutralized with oxalic acid. The oxalic acid will also neutralize...
The excess hydroxide ions must be neutralized with oxalic acid. The oxalic acid will also neutralize the hydroxide ions of the iron (III) hydroxide precipitate, releasing the iron(III) ion back into solution. Oxalic acid is chosen so that no additional anions will be present to interfere with the formation of the complex. The excess oxalate ions convert all iron present into a soluble complex ion with three oxalate ions attached to the iron(III) ion. Fe(OH)3 (s) + (aq) → _()...
The formate ion, (CHO2-), is related to the acetate ion and forms ionic salts with many...
The formate ion, (CHO2-), is related to the acetate ion and forms ionic salts with many metal ions. Assume that 11.874 g of M(CHO2)2 (where M represents the atomic symbol for a particular metal) are dissolved in water. When a solution of 0.300 M sodium sulfate is added, a white precipitate forms. The sodium sulfate solution is added until no more precipitate forms, then a few excess milliliters are added. The precipitate is filtered, washed, and dried. It has a...
BACKGROUND: Synthesis of Potassium Iron (III) Oxalate Hydrate Salt The iron(II) ions from Fe(NH4)2(SO4)2•6H2O will be precipitated as iron(II) oxalate. Fe^2+(aq) + C2O4^2-(aq) --> FeC2O4 (s) The su...
BACKGROUND: Synthesis of Potassium Iron
(III) Oxalate Hydrate Salt
The iron(II) ions from
Fe(NH4)2(SO4)2•6H2O
will be precipitated as iron(II) oxalate.
Fe^2+(aq) + C2O4^2-(aq) --> FeC2O4 (s)
The supernatant liquid, containing the ammonium and sulfate
ions, as well as excess oxalate ions and oxalic acid will be
decanted and discarded. The solid will then be re-dissolved and the
iron(II) ions will be oxidized to iron(III) ions by reaction with
hydrogen peroxide.
2Fe^2+(aq) + H2O2(aq) --> 2Fe^3+(aq) +2 OH^ - (aq)
The...
A solution containing CaCOs (100.0869 g/mol) was analyzed by precipitation of calcium oxalate, CaC204 H20 (146.1123...
A solution containing CaCOs (100.0869 g/mol) was analyzed by precipitation of calcium oxalate, CaC204 H20 (146.1123 g/mol). The masses and volumes taken can be found in the table: Clean glass funnel mass (grams) 42.2372 41.8056 42.2054 Volume of the unknown (mL) 25.0 25.0 25.0 Glass funnel with precipitate mass (8) Trial 1 Trial 2 Trial 3 42.9943 42.5652 43.0631 a. (5 points) Calculate the average molarity of Ca2* b. (5 points) Calculate the mass concentration of CaCOs (8/L)
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned...
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned colorless. Further chemical analysis revealed that the evolved gas was oxygen, and the resulting solution contains potassium sulfate and manganese () sulfate; water was also formed during the same reaction. Please with 10% aq. hydrogen peroxide, answer the followings: 1) Write down the balanced chemical equation for this reaction....
used to titrate a solution of iron(II) ions., with which it reacts according to Cerium(IV) sulfate...
used to titrate a solution of iron(II) ions., with which it reacts according to Cerium(IV) sulfate Ce4(aq)Fe2 (aq)>Ce3*(aq) + Fe3 (aq) A cerium(IV) sulfate solution is prepared by dissolving 40.47 g of Ce(SO42 in water and diluting to a total volume of 1.000 L. A total of 19.41 mL of this solution is required to reach the endpoint in a titration of a 100.0-mL sample containing Fe(aq). Determine the concentration of Fe2 in the original solution It is desired precipitate,...
Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider...
Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution: CuSO4(aq) + Na2S(aq) → CuS(s) + Na2SO4(aq) What volume of 0.104 M Na2S solution would be required to precipitate all of the copper(II) ion from 13.4 mL of 0.120 M CuSO4 solution? Volume = mL Submit Answer Try Another Version 7 item attempts remaining Generally, only the carbonates of the Group 1 elements and...
6. A 50.0 mL sample of 0.528 M NHaNO, is diluted with water to a total...
6. A 50.0 mL sample of 0.528 M NHaNO, is diluted with water to a total volume of 250.0 mL What is the ammonium nitrate concentration in the resulting solution? 7. 75.0 ml. of a 0.250M NaCI solution is added to 35.8 ml. of 0.1150M NaCOs. What is the concentration of sodium ion in the final solution? 8, 34.62 mL. of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the...
Scoring Scheme: 3-3-2-1 Part V. The chemical system containing the simultaneous equilibria involves the precipitation of calcium oxalate in the presence of a weak diprotic acid, oxalic acid: Ca2+(aq) + C2042-(aq) ; CaC204(s) H2C204(aq) H20()FH30* (aq) HC204 (aq) HC204(aq)+ H20)H3(aq)+ C2042(aq) You added 10 drops of 6 M HCI to the solution of calcium chloride and oxalic acid. Which of the following statements explains your observations? a. The addition of H30t shifts the oxalic acid equilibria to the left, decreasing...
1. When iron(II) ammonium sulfate is dissolved in water, it dissociates into its component ions. () → () + ( ) + ( ) 2. When oxalic acid is added, the iron (II) ions precipitate as iron(II) oxalate dihydrate. Fe2+ (aq) + (aq) + __H20 (1) ► ( ) + _ H(aq) 3. Next, potassium oxalate is added to the washed precipitate. Potassium oxalate dissociates into its ions in solution. At high oxalate concentrations, iron (II) oxalate combines with another...
The excess hydroxide ions must be neutralized with oxalic acid. The oxalic acid will also neutralize the hydroxide ions of the iron (III) hydroxide precipitate, releasing the iron(III) ion back into solution. Oxalic acid is chosen so that no additional anions will be present to interfere with the formation of the complex. The excess oxalate ions convert all iron present into a soluble complex ion with three oxalate ions attached to the iron(III) ion. Fe(OH)3 (s) + (aq) → _()...
BACKGROUND: Synthesis of Potassium Iron
(III) Oxalate Hydrate Salt
The iron(II) ions from
Fe(NH4)2(SO4)2•6H2O
will be precipitated as iron(II) oxalate.
Fe^2+(aq) + C2O4^2-(aq) --> FeC2O4 (s)
The supernatant liquid, containing the ammonium and sulfate
ions, as well as excess oxalate ions and oxalic acid will be
decanted and discarded. The solid will then be re-dissolved and the
iron(II) ions will be oxidized to iron(III) ions by reaction with
hydrogen peroxide.
2Fe^2+(aq) + H2O2(aq) --> 2Fe^3+(aq) +2 OH^ - (aq)
The...
A solution containing CaCOs (100.0869 g/mol) was analyzed by precipitation of calcium oxalate, CaC204 H20 (146.1123 g/mol). The masses and volumes taken can be found in the table: Clean glass funnel mass (grams) 42.2372 41.8056 42.2054 Volume of the unknown (mL) 25.0 25.0 25.0 Glass funnel with precipitate mass (8) Trial 1 Trial 2 Trial 3 42.9943 42.5652 43.0631 a. (5 points) Calculate the average molarity of Ca2* b. (5 points) Calculate the mass concentration of CaCOs (8/L)
n a pink aqueous solution of potassium permanganate, faintly addified with dilute sulfuric acid was treated the reaction took place with the evolution of gas bubbles, and the pink solution turned colorless. Further chemical analysis revealed that the evolved gas was oxygen, and the resulting solution contains potassium sulfate and manganese () sulfate; water was also formed during the same reaction. Please with 10% aq. hydrogen peroxide, answer the followings: 1) Write down the balanced chemical equation for this reaction....
used to titrate a solution of iron(II) ions., with which it reacts according to Cerium(IV) sulfate Ce4(aq)Fe2 (aq)>Ce3*(aq) + Fe3 (aq) A cerium(IV) sulfate solution is prepared by dissolving 40.47 g of Ce(SO42 in water and diluting to a total volume of 1.000 L. A total of 19.41 mL of this solution is required to reach the endpoint in a titration of a 100.0-mL sample containing Fe(aq). Determine the concentration of Fe2 in the original solution It is desired precipitate,...
Many metal ions are precipitated from a solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution: CuSO4(aq) + Na2S(aq) → CuS(s) + Na2SO4(aq) What volume of 0.104 M Na2S solution would be required to precipitate all of the copper(II) ion from 13.4 mL of 0.120 M CuSO4 solution? Volume = mL Submit Answer Try Another Version 7 item attempts remaining Generally, only the carbonates of the Group 1 elements and...
6. A 50.0 mL sample of 0.528 M NHaNO, is diluted with water to a total volume of 250.0 mL What is the ammonium nitrate concentration in the resulting solution? 7. 75.0 ml. of a 0.250M NaCI solution is added to 35.8 ml. of 0.1150M NaCOs. What is the concentration of sodium ion in the final solution? 8, 34.62 mL. of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the...
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