Question

A local FM radio station broadcasts at an energy of 6.31x10-29 kJ/photon. Calculate the frequency at which it is broadcasting. Frequency = MHz (1 MHz = 10 sec )

Answer 1

1)

Given:

E = 6.31*10^-29 KJ = 6.31*10^-26 J

use:

E = h*f

6.31*10^-26 J =(6.626*10^-34 J.s)*f

f = 9.523*10^7 Hz

f = 95.23 MHz

Answer: 95.2 MHz

2)

Given:

f = 96.7 MHz = 9.67*10^7 s-1

use:

E = h*f

=(6.626*10^-34 J.s)*(9.67*10^7) s-1

= 6.407*10^-26 J/photon

= 6.407*10^-29 KJ/photon

Answer: 6.41*10^-29 KJ/photon

3)

Given:

lambda = 1.00*10^-8 m

use:

E = h*c/lambda

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(1.00*10^-8 m)

= 1.99*10^-17 J/photon

= 1.99*10^-20 KJ/photon

Answer: 1.99*10^-20 KJ/photon