options :
- trigonal pyramidal
- bent
- tetrahedral
-trigonal planar
Ans) 1. The First Carbon or C(1) is forming 3
sigma bonds with the hydrogen atoms and Nitrogen, and Pi-bond with
the N(2)-Nitrogen atom.Thus it has sp2
hybridisation and will have a Trigonal planar
geometry.
2. The Nitrogen atom N(2) forms 1 sigma and 1 Pi-bond , but since the lone pair on Nitrogen is not delocalised ,it will form trigonal pyramidal geometry.
3. The Carbon-3 atom forms all 4 sigma bonds and has sp3 hybridisation.Thus it will have the regular tetrahedral geometry.
4. The O(4) atom forms 2 sigma bonds, but due to the presence of two lone pairs, the Lone pair-Lone pair repulsion between them causes the molecular geometry to be bent.
options : - trigonal pyramidal - bent - tetrahedral -trigonal planar Question 7 1 pts Determine...
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