Consider the redox equation below, C4HI0(g)+CreO72-(ag) + H-(aq) H&C4O4(ag) +Cr3-(aq) + H2O() The reducing agent is...

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Consider the redox equation below, C4HI0(g)+CreO72-(ag) + H-(aq) H&C4O4(ag) +Cr3-(aq) + H2O() The reducing agent is a. C4HI0(

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Answer 1

Answer #1

4. Reducing agent is a substance which itself gets oxidized (gains oxygen, loses hydrogen or loses electrons) in the reaction. We can observe that C₄H₁₀(g) gets oxidized to H₆C₄O₄ (as it gains oxygen as well as loses H). So it is the reducing agent, so option (a) is correct.

Cr₂O₇^2- loses oxygen to form Cr³⁺ so it is not the reducing agent, rather it is the oxidizing agent i.e. the substance which itself gets reduced (loses oxygen or gains electrons)

To understand the case of H⁺going to form H₂O we have to see it from the point of view of oxidation state. H has +1 oxidation state in H⁺ and in H₂O, O has -2 oxidation state and to balance it each of the two H has +1 oxidation state. So it is H⁺ is neither oxidized nor reduced.

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Consider the redox equation below, C4HI0(g)+CreO72-(ag) + H-(aq) H&C4O4(ag) +Cr3-(aq) + H2O() The reducing agent is...