here,
mass , m = 5 kg
the force 1 , F1 = 8 N j
the force 2 , F2 = 6 N i
the acceleration of the mass , a = net force /effective mass
a = ( F1 + F2) /m
a = ( 6 N i + 8 N j) /m
a = ( 6 N i + 8 N j) /5
a = ( 1.2 i + 1.6 j) m/s^2
the magnitude of acceleration , |a| = sqrt(1.2^2 + 1.6^2) = 2 m/s^2
the direction of acceleration , theta = arctan(1.6/1.2) = 53 degree
the acceleration of mass is (c) 2 m/s^2 , north of East
Two horizontal forces act on a 5.0kg mass. One force has a magnitude of 8.ON and...
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