Question

Question 1 (1 point) Small mass 100.0-g is suspended from the inelastic non stretchable string of length {L}. At time t =0 this simple pendulum makes an angle 50° with the vertical. Find the tension in the rope at the point when the pendulum has maximum kinetic energy. State your answer to the nearest tenth of the newton. (Take g=9.8m/s2). Your Answer: Answer

Answer 1

Use work energy theorem to find the speed at the lowest point where kinetic energy is maximum. Then use Newton’s law of motion for vertical circular motion at the lowest point to find the tension as shown below***********************************************************************************************
Check the answer and let me know immediately if you find something wrong or missing... I will rectify the mistakes asap if any

The pendulum has maximum kinetic energy at bottom of its motion when the string is vertical, h = L(2-coso) Info from work energy theorem, Wgravity = AKE » mgh = // m (Vg² - VA²) » 2gh = V²-0 - VB = 52gh Now, at the bottom, T-mg = mvg² tos wher- en mus} TuBelm - Bm - 2 E E = bm-I rosos-t) burz € (osos-I) burz = bm-I π π T = mg (1+ 2(2-COSO) = mg (3-2005o), = (0:18919.8 m/s2)(3-2c0s50°) = [1.7N