Problem 2: An ice-skater, as we mentioned in lecture, in order to increase her angular velocity...
1. An ice skater spins on the ice with her arms positioned tight against her body. In this position, she has a moment of inertia of 1.3 kg m2 and an angular speed of 15 rad/s. If the ice skater then stretches out her arms, and her angular speed slows to 6.0 rad/s, what is her moment of inertia with her arms outstretched? 3.64 kg m2 4.91 kg m2 3.25 kg.m2 4.39 kg m2 6.11 kg m2 А В С...
3. An ice skater starts spinning at a rate of 2.0 rev/s with their arms extended. They then pull their arms in toward their body reducing their moment of inertia by ¼, what is the angular velocity of the skater with their arms pulled in?
An ice skater spins, with her arms and one leg outstretched, and achieves an angular velocity of 2 rad/s. when she pulls in her arms, her moment of inertia decreases to 65% its original value. what is her new angular velocity?
A figure-skater finishes her routine with a dramatic spin. Initially, she spins at a rate of 1.3 rev/sec. During this time, the figure skater has her arms stretched out. In each hand, she holds a mass of 2.3 kg at a distance of 0.65m from the center of her body. She then pulls her arms in so that the masses are tucked into the middle of her chest. The moment of inertia of her head-torso-legs remains fixed at 24 kg-m2....
An ice skater is spinning at a particular rotational velocity when she decides to bring her arms inward, thus reducing her moment of inertia. If she reduces her moment of inertia by 20.0%, her rotational velocity will increase by what percent?
Natalie is an accomplished ice skater with hopes of competing in the 2022 Winter Olympics in Beijing. One of her standard moves is to spin on point. She starts spinning at 3.5 rev/s with her arms outstretched and an associated moment of inertia I = 6.4 kg ∙ m2. Natalie then brings her arms in and decreases her moment of inertia to I = 1.8 kg ∙ m2. What is her final angular speed? A. 10 rev/s B. 3.5 rev/s...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act. a) Determine her initial angular speed in rad/s. (1 marks) b) Calculate her final angular speed in RPM (4 marks) c) Calculate the period of rotation when she is at her final speed (1...
A figure skater is spinning on frictionless ice. Treat the figure skater as a sphere with radius R=.4m and mass M=60kg. The skater is holding onto a massless string attached to a weighted ball of m=10kg. The skater is initially spinning at an angular speed w0 of 2pi radians per second (1 rev/s) with a sting radius of r=1m. Moment of inertia for a sphere is I=(2/5)MR^2. 1.) What is the initial total rotational inertia of the skater and ball?...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act. a) Determine her initial angular speed in rad/s. (1 marks) b) Calculate her final angular speed in RPM (4 marks) c) Calculate the period of rotation when she is at her final speed (1...