An ice skater spins, with her arms and one leg outstretched, and achieves an angular velocity...
1. An ice skater spins on the ice with her arms positioned tight against her body. In this position, she has a moment of inertia of 1.3 kg m2 and an angular speed of 15 rad/s. If the ice skater then stretches out her arms, and her angular speed slows to 6.0 rad/s, what is her moment of inertia with her arms outstretched? 3.64 kg m2 4.91 kg m2 3.25 kg.m2 4.39 kg m2 6.11 kg m2 А В С...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?
An ice skater has a moment of inertia of 5.0 kg-m2 when her arms are outstretched. At this time she is spinning at 3.0 revolutions per second (rps). If she pulls in her arms and decreases her moment of inertia to 2.0 kg-m2, how fast will she be spinning? A) 7.5 rps B) 8.4 rps C) 2.0 rps D) 10 rps E) 3.3 rps
A skater has a moment of inertia of 4kg.m2 when both her arms are outstretched rotating at 60 rpm. When she draws her arms in her moment of inertia drops to 0.8kg.m2 . What is her angular momentum and new speed of rotation in rpm?
A figure skater is spinning slowly with arms outstretched. She brings her arms in close to her body and her moment of inertia decreases by 12. By what factor does her rotational Kinetic energy change?
A skater holds her arms outstretched as she spins at 173 rpm. What is the speed of her hands if they are 146 cm apart?
A figure skater spins with her arms outstretches at a rate of 10 rev/s. When she pulls her arms closer to her body, her moment of inertial about the spin axis decreased by 10%, what is the skaters new rotational rate in rev/sec?
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is the skater’s resulting angular velocity?
Problem 2: An ice-skater, as we mentioned in lecture, in order to increase her angular velocity from 2.0 rev per 1.3 sec to 3.5 rev per sec she needs to decrease her moment of inertia to a value of 4.6 kg m/sec by pulling hers arms towards her body. a) Find her initial moment of inertia when her arms are out-stretched. b) Calculate the rotational kinetic energy for each case.