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Determine the out.ph, and pOH of a solution with a H+] [4.6 x 10 Mat 25°C. Jour] = pt = pOH = Determine the [ .pl, w pH of a

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O Cot} = 4.6810 M 13 - P17x1õtm [ou] = 2.17 80 m) pH = -log [ ut ] = -log (4680) pht = 100 34) DOH. = idyaph = 14 - 10.34 D③ [ot] = 3.180 m [ht] = 1014 - coth = 3.23X1000m [ou] 3.1x10m pH = -log[ut] 2-ing (323 x640) [pH = 9.49] pot = 14 -pi 2.199.4pH = 10.45 - log Cut = 104 [CH] = 3.548810 m [on] = 10th 10th Clot 3.548 404 ( [ou]= 2.818 8150 m polt = 14 - PH = 14-10.45 ppot = 10.73 - log [of] = 10.73 ( [on] = 1.862x10lm [ist] = 104 = 10th Tout] U8 Gero [ {H} = 5.37 x103 M) рия 14 — рон =14-10.

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