Question

Exercise 1. Lab Preparation. Q1) 25.00 ml of 0.10 M COCI, solution is needed for this experiment. Show all calculations associated with the creation of this solution. 25.00mil IL 10.10m Coch 100oment Timor coche 0.32g Colla Q2) Describe how to make 25.00 mL of 0.10 M CoCl, solution. Be specific. Prepare the solution. Add 0.32g of Collz in 25.com, of water to preport 0.70M Collz Solomon 93) Determine the amount of 1.00 M HCl stock solution needed to form 100 ml of 1.50x10' M HCI solution. Show all work. Q4) Determine the amount of 1.00x10' M stock NaOH solution needed to make 100 mL of 1.50x10 M NaOH solution. Show all work. Using good dilution techniques, make the solutions in Q3 and 24. Use a graduated cylinder to measure out and transfer the stock solutions. Remember, graduate cylinders are rated TC NOT TD. Therefore, you will need to rinse the graduated cylinder many times with distilled water and transfer these washings to the volumetric flask. Using a Bunsen burner, boil roughly 300 mL of tap water. Notice the extra ring around the beaker to prevent accidents. Also, make sure the beaker is on a wire gauze. If not, the glass may "weld" to the ring stand! Once the water boils, pay attention. Do not let the water level drop too low. Setup an ice bath. Add water to the ice to allow good thermal contact with anything placed in bath. 101

Answer 1

3) Mstock - IM Ma V=100ml Vstock =? M=115x16 M. Mv=MVZ Stock diluted solution IM XV = 1.5x102 M X loomL TV = 1.5mL! e. 1.5mL stock solution (100-115) 98.5ml water to make toome of 1.5x15²M HCl. Mstock - Ixlolm M=1.5x16M Vst = ? V= loomL Mavi = M2 V Stock Diluted lodov = 1.5x1024 xloomL Vst. z 15ml " 15ml a stock solution (100-15) 85mL a water. required to make 100 mL of 1.5x10²M Adletion