Question

PHYS 111 Laboratory - Pre-lab #13 (ARCHIMEDES' PRINCIPLE) Student Name: Lab Day and Time: Due at the beginning of lab. All answers must be legibly handwritten for credit. Show all work. References: lab manual, textbook Ch. 13.1 -13.3. 1) (lab manual and Ch. 13.3) What is Archimedes' Principle? 2) (lab manual and Ch. 13.1) A cylinder of an unknown material has a mass mi = 0.0226 kg, a diameter d=0.0191 (remember this is two times the radius), and a height h = 0.0292 m. a. Using this information, calculate its volume Vi. b. [lab manual Eq. (1) or (6), textbook Eq. 13.1] Using your answer for part 2a, calculate the density of the cylinder. This calculation is Method 1 in the procedure. 3) [lab manual Eq. (1) or (6), Eqn. 13.1, and Fig. 13.13] The same cylinder is submerged in water. It displaces me=0.0088 kg of water. The density of water is pe= 1000 kg/m'. a. Using this information, what is the volume of the water and the cylinder)? b. Using your answer for part 3a and mi, calculate the density of the cylinder. This calculation is very similar to Method 2 in the procedure. 4) [lab manual Eq. (10), Ch. 13.1 and 13.3] The same cylinder is weighed using a force probe and has weight in air W = 0.225 N. It is then submerged in water (pr= 1000 kg/m) where the force probe measures Tr=0.146 N. a. Calculate the density of the cylinder. This calculation is Method 3 in the procedure. b. (Example 13.5) Read the text example to understand how Archimedes determined that the crown was not made of pure gold. Did the shape of the crown matter? Explain.

Answer 1

(1) Archimede's Principle e states that when a body is partially or completely submerged in water a liquid than the upward force acting on it is equal to weight of fluid it displaus. The displaced fluid has the same volume as . the submerged part of the body. (2) 6 VE 12h =314x10 0101 )'X 0029 2 V= 8.36x10-6 m² Ang b) Density de m = 0.33310-6 d=2.7038103 kg/m3 Ans (3) (9 Volume of water it displaces is vs un 2000 of the cylinder. - above VE88 x10 m3 volume is equal to the volume (bl The deņ = 0.0226 d=2.568 X103 kg/m3 9) Change in weight - bugyanuy force = 0225 -0°146 N $ i mass of displaced = 0.079 N water m= 0079 9 i Volume V= 0.079 -0079 ag 1000x9.8 is v=8.00X06 m3