calculate the molarity of each of the following solutions: 1. 4.45 mol of LiCl in 2.20...

Question

Question

calculate the molarity of each of the following solutions:

1. 4.45 mol of LiCl in 2.20 L solution

2. 28.93 g C6H12O6 in 1.11 L of solution

3. 34.3 mg NaCl in 119.0 mL of solution

Answer 1

Answer #1

o mole solute molarity - Jolume (2) = 4, y = 2.62 mg 2 mol Congo - 28.93 - 0.161 mol 80 17 Molarity - molarity = 0.161 Toll =

Answer 2

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