Calculate the molarity of the two solutions. a) 0.350 mol of NaOH in 2.35 L of solution. b) 13.3 g of NaCl in 811 mL of solution.
a)
Molarity = number of moles of NaOH / volume of solutioni in L
Molarity = 0.350 mol / 2.35 L = 0.149 M
b)
Number of moles of NaCl = 13.3 g / 58.44 g.mol^-1 = 0.228 mole
Molarity of NaCl = number of moles of naCl / volume of solution in L
Molarity of NaCl = 0.228 mole / 0.811 L = 0.281 M
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