Question

3 attempts left Check my work Be sure to answer all parts. Rank the members of each set of compounds in order of increasing ionic character of their bonds. (a) HBr, HCI, HI O HCI < HBr <HI HBr <HCI <HI HI <HBr <HCI (b) H40, CH4, HF O H,0 <CH, <HF HF<H,0 <CH CH, <H2O <HF (c) SCI, PCI3, SiC14 SCI, <PCI, <SICIA SICI, < PCI, <SC12 PCI, <SCI, < SICH < Prev 14 of 14 !!! Next

Answer 1

Ionic character depends on the diffeunce in edeponegativity between the two bonded atoms. Greater the elechon fativery difference, greater is the ionic character H- u electronegativity Th= 2.1 Elechronegativity gas 3.0 V ALID H-BY s portI = 2.5 H-1 Bra atig DE Fero HU = De for H Br= 3-0 -2.1 = 0.9 2.8-2.9 = 0.7 2.5- 9:1 = 0.4 fra an HET = до овдех и на 7 hвҮҮНІ <he option D correct. le . HIL HBr

electora gahvity 90 = 3.5 Elechoney. J F = 40 Elechones. yc = 25 For HF = 40-201 = .9 For CH4 = 2.5-2.1 = 0.4 For 420= 3.5-2.1 = 1.4 so order is cha<H₂OCHF optimo correct. c) sela Paz silla Elechones. y s = 2.5 Elechones y d = 3.5 P = 2:1 Si = 1.8

DE for SCI2 = 3.5-7.5 = 10 Pdz = 3.5- 2:1 = 1.4 Sic14 = 3.5-1.8 = 1.7 so order is sc <PC 3 < side oprim A consect