Marginal revenue function = d(TR)/dQ
MR = d(150+50Q-5Q2)/dQ = 50-10Q
MC = d(TC)/dQ
MC = d(100+6Q)/dQ = 6
Q | TR=150+50Q - 5Q2 | TC =100+6Q | MC | MR | Marginal Profit= MR - MC |
0 | 150 | 100 | - | - | - |
1 | 195 | 106 | 6 | 45 | 39 |
2 | 230 | 112 | 6 | 35 | 29 |
3 | 255 | 118 | 6 | 25 | 19 |
4 | 270 | 124 | 6 | 15 | 9 |
5 | 275 | 130 | 6 | 5 | -1 |
6 | 270 | 136 | 6 | -5 | -11 |
7 | 255 | 142 | 6 | -15 | -21 |
8 | 230 | 148 | 6 | -25 | -31 |
9 | 195 | 154 | 6 | -35 | -41 |
10 | 150 | 160 | 6 | -45 | -51 |
Profit (TR-TC) |
50 |
89 |
118 |
137 |
146 |
145 |
134 |
113 |
82 |
41 |
-10 |
B) At Q = 4 the profit is maximum
C) At the level of Q = 4 the marginal revenue is decreasing and the marginal cost is constant.
D) At Q = 4 the marginal profit is 9
E) When MR = MC we get the maximum quantity which maximize profit
MR = MC
50-10Q = 6
44 = 10Q
Q = 4.4
So the value is approximately equal to 4
Assume TR(Q) = 150 + 500-50° and TC(Q) = 100 + 6Q Create a table in...
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