Question
can someone help
ts) Given the following reaction in a non-rigid, but closed container: Heat +CaCO3(-) + H2O + CO2(g) + 2HCO3(aq) + Cat2(aq)
ts) Given the following reaction in a non-rigid, but closed container: Heat +CaCO3(-) + H2O + CO2(g) + 2HCO3–(aq) + Cat2(aq)
0 0
Add a comment Improve this question Transcribed image text
Answer #1

The given reaction takes place in a closed container. That means there is only heat is exchange between the system and surrounding and there is no exchange of matter.

The given reaction is Heat + CaCO3 + H2O + CO2 ------------> 2HCO3 - + Ca+2 is present at equilibrium

Now the change in direction of equilibrium due to change in different conditions will be determined according to Li-Chatelier's Principle

1-

CaCO3 is added to the container- According to Li-Chatelier's Principle, if we increase the concentration of the reactant, the equilibrium shifts to right to form more product and re-establish the equilibrium.

Since the added CaCO3 is a reactant, thus the equilibrium shifts to right.

2-

Ar(g) is added to the container- Since the system is closed and there is no exchange between the system and surrounding, And the volume of the system remains constant.

According to Li-Chatelier's Principle, when an inert gas is added to the system in equilibrium at constant volume there will be no effect on the equilibrium.

3-

CO2 is removed from the container- According to Li-Chatelier's Principle, if we decrease the concentration of the product, the equilibrium shifts to right to form more product and re-establish the equilibrium.

Since the removed CO2 is a product, thus the equilibrium shifts to right.

4-

In the given reaction, heat is written in the reactant side. Thus this is an Endothermic reaction. That means heat also act as ac reactant. Thus when we add heat or heat the container, equilibrium shifts to right to form more product and re-establish the equilibrium.

5-

When Ca(NO3)2 is added. - We know Ca(NO3)2 is soluble in water. Thus when it is adde to the solution, it dissociates as- Ca(NO3)2 ------------> Ca+2 + 2 NO3-

That means due to addition of Ca(NO3)2, amount of Ca+2 increases.

Now Since the added Ca+2 is a product, thus the equilibrium shifts to left to form more reactant and re-establich the equilibrium.

Add a comment
Know the answer?
Add Answer to:
can someone help ts) Given the following reaction in a non-rigid, but closed container: Heat +CaCO3(-)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Consider the following reaction at equilibrium, CaCO3(s) ↔ CaO(s) + CO2(g). Which of the following statements...

    Consider the following reaction at equilibrium, CaCO3(s) ↔ CaO(s) + CO2(g). Which of the following statements are true regarding this equilibrium? Select all that are True. a) If CaO(s) is added from the equilibrium mixture the reaction will remain unchanged. b) If CaO(s) is removed from the equilibrium mixture the reaction will shift to the left. c) If CO2(g) is added to the equilibrium mixture the reaction will shift to the right. d) If CO2(g) is added to the equilibrium...

  • 1. The initial concentrations of reactants and products for this reaction are given below. N2(g) +...

    1. The initial concentrations of reactants and products for this reaction are given below. N2(g) + O2(g) ⇄ 2NO(g) Calculate Q for this reaction. Answer this to one decimal place (e.g. 10.2) The initial concentration of N2 is 1.0 M The initial concentration of O2 is 1.0 M The initial concentration of NO is 2.5 M 2. The reaction below is not at equilibria and Q = 1.7. The equilibrium constant is K = 0.230. 2SO3(g) ⇌ 2SO2(g) + O2(g)...

  • 1. In the following reaction at equilibrium, what will happen if more CO(g) is added? COCI:(9)...

    1. In the following reaction at equilibrium, what will happen if more CO(g) is added? COCI:(9) CO(g) + Cl (9) A) reaction will shift to the right B) reaction will shift to the left C) nothing will happen D) the equilibrium constant will change E) not enough information given to predict 2. The following reaction is exothermic (with A and B reactants) and at equilibrium. What will happen if heat is added? A+B 2 C + D A) more C...

  • help on number 3 here is lab we did EXPERIMENT 19 An Analysis of Commercial Antacids...

    help on number 3 here is lab we did EXPERIMENT 19 An Analysis of Commercial Antacids Rolaids Alka Seltzer OBJECTIVES: Determine the per gram neutralizing ability of a commercial antacio Determine the per gram neutralizing ability of sodium bicarbonate Compare the effectiveness of several antacids. INTRODUCTION: "How do you spell relief two hecimie The parietal cells in the stomach secrete sufficient hydrochloric aci 0.10 M The flow of HCl increases when food enters the stomach and so acid secrete sufficient...

  • I need helppp with my AP chem lab

    Purpose: To calculate the amount of AgNO3 present in an unknown solution of water through the process of gravimetric analysis with NaCl.   Background: Have you ever had difficulty lathering soap or find that the scum in your shower constantly needs to be removed? These are signs of “hard water.” Soap does not lather well in hard water because metal ions, such as Ca2+, form precipitates, creating “soap scum.” A precipitate is an insoluble compound that forms when soluble ions in...

  • help please? this was the only other information given REPORT SHEET Determination of the Solubility-Product Constant...

    help please? this was the only other information given REPORT SHEET Determination of the Solubility-Product Constant for a Sparingly Soluble Salt EXPERIMENT 8 A. Preparation of a Calibration Curve Initial (Cro121 0.0024 M Absorbance 5 mL Volume of 0.0024 M K Cro Total volume 1. I mL 100 mL 2. 100ML 3. 10 mL 100ml 4. 15 mL 100 ML Molar extinction coefficient for [CrO2) [Cro,2) 2.4x100M 12x1044 2.4810M 3.6810M 0.04) 2037.37 0.85 1.13 2. 3. Average molar extinction coefficient...

  • CHEM 1033, Sample Exam II (Homework) Chapters 3,4,6 Name: 1. What volume of 0.132 M KOH...

    CHEM 1033, Sample Exam II (Homework) Chapters 3,4,6 Name: 1. What volume of 0.132 M KOH solution would react completely with 25.8 ml. of 0.198 M HCl according to the following cquation? HCI+KOH --->KCI+H.O a) 86.4 ml. b) 25.7 ml. c) 38.7 ml d) 17.2 ml. 2. Which one of the following is a strong soluble base? a) Ni(OH): b) Mg(OH): c) RLOH d) ChOH) c) Fe(OH) 3. Which one of the following is a strong acid? a) HF b)...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT